If n(X)= ^m C_6 , then the value of m is

(S=\{1,2,3,4,5,6\} \quad R: S → S) Number of elements in $R=6$ and for each ((a, b) \in R ;|a-b| \geq 2) $X →$ set of all relation $R: S → S$ If (a=1, b=3,4,5,6 $\rightarrow($4)) (a=2, b=4,5,6 $\rightarrow($3)) (a=3, b=1,5,6 $\rightarrow($3)) (a=4, b=1,2,6 $\rightarrow($3)) (a=5, b=1,2,3 $\rightarrow($3)) (a=6, b=1,2,3,4 $\rightarrow($4)) Total number of ordered pairs $(a, b)$ s.t. (|a-b| \geq 2 =20) (\therefore n(X)=) number of elements in ($\mathrm{X}={ }^{20}$C_6) (\therefore m=20)