JEE Advanced 2024Paper 2
- Exam
- JEE Advanced
- Year
- 2024
- Paper
- Paper 2
- Subject
- Mathematics
- Chapter
- Sets and Relations
JEE Advanced 2024 · Paper 2 · Mathematics · Sets and Relations
If the value of n(Y)+n(Z) is k^2 , then |k| is Let (S=\...
If the value of is , then is
Let (S=\{1,2,3,4,5,6\}) and be the set of all relations from to that satisfy both the following properties:
i. has exactly 6 elements.
ii. For each ((a, b) \in R), we have (|a-b| \geq 2).
Let (Y=\{R \in X) : The range of has exactly one element (\}) and (Z=\{R \in X: R) is a function from to (S\}).
Let denote the number of elements in a set .
Correct answer
0
Step-by-step solution
given so if
i.e. Total elements in is
Now for ,
range of has exactly one element i.e. second elements must be constant in and since must have 6 element so it is not possible to satisfy both condition so .
no. of relation that are function will be $$