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JEE Advanced 2006
Exam
JEE Advanced
Year
2006
Subject
Mathematics
Chapter
Vector Algebra

JEE Advanced 2006 · Mathematics · Vector Algebra

Let a= i +2 j + k , b= i - j + k , c= i + j - k . A vector coplanar...

Let a=i^+2j^+k^,b=i^−j^+k^,c=i^+j^−k^\mathbf{a}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{c}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}. A vector coplanar to a\mathbf{a} and b\mathbf{b} has a projection along c of magnitude 13\frac{1}{\sqrt{3}}, then the vector is

Options

  1. A4i^−j^+4k^4 \hat{\mathbf{i}}-\hat{\mathbf{j}}+4 \hat{\mathbf{k}}
  2. B4i^+j^−4k^4 \hat{\mathbf{i}}+\hat{\mathbf{j}}-4 \hat{\mathbf{k}}
  3. C2i^+j^+k^2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}
  4. DNone of these

Correct answer

A. 4i^−j^+4k^4 \hat{\mathbf{i}}-\hat{\mathbf{j}}+4 \hat{\mathbf{k}}

Step-by-step solution

Let vector r\mathbf{r} be coplanar to aand\mathbf{a} and\mathbf{b}..∴r=a+tb⇒r=(i^+2j^+k^)+t(i^−j^+k^)=i^(1+t)+j^(2−t)+k^(1+t)\begin{array}{ll} \therefore& \mathbf{r}=\mathbf{a}+ t \mathbf{b} \\ \Rightarrow & \mathbf{r}=(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+\hat{\mathbf{k}})+t(\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}})=\hat{\mathbf{i}}(1+t)+\hat{\mathbf{j}}(2-t)+\hat{\mathbf{k}}(1+t) \end{array}TheprojectionofThe projection of\mathbf{r}onon\mathbf{c}=\frac{1}{\sqrt{3}} \Rightarrow \frac{\mathbf{r} \cdot \mathbf{c}}{|\mathbf{c}|}=\frac{1}{\sqrt{3}}\Rightarrow \frac{|1 \cdot(1+t)+1 \cdot(2-t)-1 \cdot(1+t)|}{\sqrt{3}}=\frac{1}{\sqrt{3}}\Rightarrow|2-t|=\pm 1 \Rightarrow t=1or3When,or 3 When,t=1wehavewe have\mathbf{r}=2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+2 \hat{\mathbf{k}}When,When,t=3wehavewe have\mathbf{r}=4 \hat{\mathbf{i}}-\hat{\mathbf{j}}+4 \hat{\mathbf{k}}$
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