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JEE Advanced 2006
Exam
JEE Advanced
Year
2006
Subject
Mathematics
Chapter
Vector Algebra

JEE Advanced 2006 · Mathematics · Vector Algebra

Let A be vector parallel to line of intersection of planes P_1 and...

Let A\mathbf{A} be vector parallel to line of intersection of planes P1P_1 and P2P_2 through origin. P1P_1 is parallel to the vectors 2j^+3k^2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}} and 4j^−3k^4 \hat{\mathbf{j}}-3 \hat{\mathbf{k}} and P2P_2 is parallel to j^−k^\hat{\mathbf{j}}-\hat{\mathbf{k}} and 3i^+3j^3 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}, then the angle between vector A\mathbf{A} and 2i^+j^−2k^2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}} is

Options

  1. Aπ2\frac{\pi}{2}
  2. Bπ4\frac{\pi}{4}
  3. Cπ6\frac{\pi}{6}
  4. D3π4\frac{3 \pi}{4}

Correct answer

B. π4\frac{\pi}{4}

Step-by-step solution

Let vector AO\mathbf{A O} be parallel to line of intersection of planes P1andP2P_1 and P_2 through, i.e. [(2j^+3k^)×(4j^−3k^)]×[(j^−k^)×(3i^+3j^)]=54(j^−k^).∴ Angle between 54(j^−k^) and (2i^+j^−2k^)⇒cos⁡θ=±(54+1083.54⋅2)=±12∴θ=π4,3π4\begin{aligned}& {[(2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}) \times(4 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})] \times[(\hat{\mathbf{j}}-\hat{\mathbf{k}}) \times(3 \hat{\mathbf{i}}+3 \hat{\mathbf{j}})]=54(\hat{\mathbf{j}}-\hat{\mathbf{k}}).} \\ & \therefore \text{ Angle between }54(\hat{\mathbf{j}}-\hat{\mathbf{k}}) \text{ and }(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}) \\ & \Rightarrow \cos \theta=\pm\left(\frac{54+108}{3.54 \cdot \sqrt{2}}\right)=\pm \frac{1}{\sqrt{2}}\\ & \therefore \quad \theta=\frac{\pi}{4}, \frac{3 \pi}{4} \end{aligned}
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