JEE Advanced2006MathematicsVector AlgebraActual
Match the following
Options
- A(i) (a), (ii) (b), (iii) (d), (iv) (c)
- B(i) (c), (ii) (a), (iii) (b), (iv) (d)
- C(i) (a), (ii) (d), (iii) (b), (iv) (c)
- D(i) (b), (ii) (a), (iii) (c), (iv) (d)
Correct answer
D. (i) (b), (ii) (a), (iii) (c), (iv) (d)
Step-by-step solution
(i) Solved the two equations, say, i.e. x+y=|a| and a x-y=1 , we get x= |a|+1 a+1 >0 and y= |a|-1 a+1 >0 when a+1>0 ; we get a>1 a₀=1 (ii) We have, a = i + j + k a k = Now, k ( k a )=( k a )-( k k ) a = k -( i + j + k ) i + j =0 = =0 Also, + + =2 =2 (iv) A B C+ A B A B+ A B= (A-B) array lc & (A-B) 1 (A-B)=1 & C=1 array