In a circuit, a metal filament lamp is connected in series with a capacitor of capacitance C F across a 200 ~V , 50 ~Hz supply. The power consumed by the lamp is 500 ~W while the voltage drop across it is 100 ~V . Assume that there is no inductive load in the circuit. Take r m s values of the voltages. The magnitude of the phaseangle (in degrees) between the current and the supply voltage is . Assume, 3 5 . The value

Step-by-step solution

Given, P = 500   W V R = 100   V f = 50   Hz V r m s = 200   V P = V R 2 R ⇒ R = V R 2 P ⇒ R = 100 2 500 ∴     R = 20   Ω Now current in the circuit, i = i r m s = voltage   across   resistor resistance i = 100 20 i = 5   A Phasor diagram of the given circuit for voltage, Now, V 2 = V C 2 + V R 2 ⇒ 200 2 = V C 2 + 100 2 ⇒ V C = 100 3   V Now, V C = 100 3   V = I X C ⇒ X C = 100 3 5 = 20 3   Ω and X C = 1 2