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JEE Main202224 Jun 2022Morning ShiftPhysicsAlternating CurrentActual

As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz . The instantaneous voltage of the source is 0 V when the peak value of current is a π A . The value of a is _____ .

Correct answer

0

Step-by-step solution

The reactance of the given inductor is, X L = ω L = 2 π f L = 2 π × 50 × 0 . 2 = 20 π   Ω . The maximum current in the given circuit will be, i 0 = 2 V r m s X L = 2 × 220 20 π = 242 π   A Therefore, a = 242

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