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JEE Advanced 2010Paper 1
Exam
JEE Advanced
Year
2010
Paper
Paper 1
Subject
Physics
Chapter
Alternating Current

JEE Advanced 2010 · Paper 1 · Physics · Alternating Current

An AC voltage source of variable angular frequency ω and fixed...

An AC voltage source of variable angular frequency ω\omega and fixed amplitude V0V_0 is connected in series with a capacitance CC and an electric bulb of resistance RR (inductance zero). When ω\omega is increased

Options

  1. Athe bulb glows dimmer
  2. Bthe bulb glows brighter
  3. Ctotal impedance of the circuit is unchanged
  4. Dtotal impedance of the circuit increases

Correct answer

B. the bulb glows brighter

Step-by-step solution

Z=R2+XC2:Irms=VrmsZ:P=Irms2RZ=\sqrt{R^2+X_C^2}: I_{\mathrm{rms}}=\frac{V_{\mathrm{rms}}}{Z}: P=I_{\mathrm{rms}}^2 R where, XC=1ωC\quad X_C=\frac{1}{\omega C} As ω\omega is increased, XCX_C will decrease or ZZ will decrease. Hence ImmsI_{\mathrm{mms}} or PP will increase. Therefore, bulb glows brighter. Hence the correct option is (b).
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