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JEE Main 2010
Exam
JEE Main
Year
2010
Subject
Physics
Chapter
Alternating Current

JEE Main 2010 · Physics · Alternating Current

In a series LCR circuit R=200 and the voltage and the frequency of...

In a series LCR circuit R=200ΩR=200 \Omega and the voltage and the frequency of the main supply is 220 V220 \mathrm{~V} and 50 Hz50 \mathrm{~Hz} respectively. On taking out the capacitance from the circuit the current lags behind the voltage by 30∘30^{\circ}. On taking out the inductor from the circuit the current leads the voltage by 30∘30^{\circ}. The power dissipated in the LCR circuit is

Options

  1. A305 W305 \mathrm{~W}
  2. B210 W210 \mathrm{~W}
  3. CZero W
  4. D242 W242 \mathrm{~W}

Correct answer

D. 242 W242 \mathrm{~W}

Step-by-step solution

The given circuit is under resonance as XL=XCX_L=X_C Hence power dissipated in the circuit is P=V2R=\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}}=242  W\mathrm{~W}
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