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JEE Advanced 2025Paper 1
Exam
JEE Advanced
Year
2025
Paper
Paper 1
Subject
Physics
Chapter
Atomic Physics

JEE Advanced 2025 · Paper 1 · Physics · Atomic Physics

List-I shows various functional dependencies of energy (E) on the...

List-I shows various functional dependencies of energy (E)(E) on the atomic number (Z)(Z). Energies associated with certain phenomena are given in List-II.\nChoose the option that describes the correct match between the entries in List-I to those in List-II.
List-I List-II
(P)(P) E∝Z2E \propto Z^2 (1)(1) energy of characteristic x-rays
(Q)(Q) E∝(Z−1)2E \propto(Z-1)^2 (2)(2) electrostatic part of the nuclear binding energy for stable nuclei with mass numbers in the range 30 to 170
(R)(R) E∝Z(Z−1)E \propto Z(Z-1) (3)(3) energy of continuous x-rays
(S)(S) EE is practically independent of ZZ (4)(4) average nuclear binding energy per nucleon for stable nuclei with mass number in the range 30 to 170
(5)(5) energy of radiation due to electronic transitions from hydrogen-like atoms

Options

  1. AP→4,Q→3,R→1, S→2\mathrm{P} \rightarrow 4, \mathrm{Q} \rightarrow 3, \mathrm{R} \rightarrow 1, \mathrm{~S} \rightarrow 2
  2. BP→5,Q→2,R→1, S→4\mathrm{P} \rightarrow 5, \mathrm{Q} \rightarrow 2, \mathrm{R} \rightarrow 1, \mathrm{~S} \rightarrow 4
  3. CP→5,Q→1,R→2, S→4\mathrm{P} \rightarrow 5, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 4
  4. DP→3,Q→2,R→1, S→5\mathrm{P} \rightarrow 3, \mathrm{Q} \rightarrow 2, \mathrm{R} \rightarrow 1, \mathrm{~S} \rightarrow 5

Correct answer

C. P→5,Q→1,R→2, S→4\mathrm{P} \rightarrow 5, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 4

Step-by-step solution

(P) Energy of H -like atom is E=−13.6Z2n2 So E∝Z2P→(5)\begin{aligned} & \mathrm{E}=-13.6 \frac{\mathrm{Z}^2}{\mathrm{n}^2} \text{ So } \\ & \mathrm{E} \propto \mathrm{Z}^2 \\ & \mathrm{P} \rightarrow(5)\end{aligned} (Q) Energy of characteristic X-ray by moseley's correction E=−13.6(Z−1)2[1n12−1n22] So E∝(Z−1)2Q→(1)\begin{aligned} & E=-13.6(Z-1)^2\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right] \text{ So } \\ & E \propto(Z-1)^2 \\ & Q \rightarrow(1)\end{aligned} (R) Electrostatics binding energy is proportional to Z(Z−1)R→(2)Z(Z-1) R \rightarrow(2) (S) For stable nuclei with mass no. in range 30 to 170 . Binding energy per nucleon is constant \& graph is straight line S→(4)S \rightarrow(4) Ans. (C) is correct
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