A hydrogen atom, initially at rest in its ground state, absorbs a photon of frequency v₁ and ejects the electron with a kinetic energy of 10 eV . The electron then combines with a positron at rest to form a positronium atom in its ground st

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A hydrogen atom, initially at rest in its ground state, absorbs a photon of frequency v₁ and ejects the electron with a kinetic energy of 10 eV . The electron then combines with a positron at rest to form a positronium atom in its ground state and simultaneously emits a photon of frequency v₂ . The center of mass of the resulting positronium atom moves with a kinetic energy of 5 eV . It is given that positron has the

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Correct answer: 11.8

h v₁=13.6+10=23.6 eV ....(1) Energy of positronium in ground state aligned & =-13.6 m ( z n )^2 eV & =-13.6 1 2 eV =-6.8 eV aligned So to make positronium 6.8 eV must release & 5 eV is the KE of COM . So total energy of photon released (h v₂ ) will be : h v₂=(10-5)+6.8=11.8 eV ....(2) Difference in energy =23.6-11.8=11.8 eV

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