In a scattering experiment, a particle of mass $2 m$ collides with another particle of mass $m$ , which is initially at rest. Assuming the collision to be perfectly elastic, the maximum angular deviation $\theta$ of the heavier particle, as shown in the figure, in radians is:

Question

In a scattering experiment, a particle of mass

2 m

collides with another particle of mass

m

, which is initially at rest. Assuming the collision to be perfectly elastic, the maximum angular deviation

\theta

of the heavier particle, as shown in the figure, in radians is:
In a scattering experiment, a particle of mass 2 m collides with another particle of mass m , which is initially at

In a scattering experiment, a particle of mass 2 m collides with another particle of mass m , which is initially at

Quantrex Academy · Accepted Answer

Correct answer: D. (π)/(6)

2 m v_1=2 m v_ 1 f θ+2 m v_ 2 f φ ....(i) 2 m m_ 1 f θ=m v_ 2 f φ ....(ii) (1)/(2)(2 m) v_1^2+(1)/(2) m(0)^2=(1)/(2)(2 m) v_ 1 f ^2+(1)/(2) m v_ 2 f ^2 2 v_1^2=2 v_ 1 f ^2+v_ 2 f ^2 ....(iii) From (i), (ii), (iii), aligned & 3 v_ 1 f ^2-4 v_1 v_ 1 f θ+v_1^2=0 & (-4 v_1 θ)^2-4(3)(v_1^2) ≥ 0 & ^2 θ ≥ (3)/(4) & ^2 θ ≥ 3 2 & θ=(π)/(6) aligned

In a scattering experiment, a particle of mass 2 m collides with...

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