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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Main 2025 · 7 April · Morning Shift · Physics · Center of Mass, Momentum and Collision

A rod of length 5 L is bent right angle keeping one side length as...

A rod of length 5 L is bent right angle keeping one side length as 2 L.
A rod of length 5 L is bent right angle keeping one side length as 2 L. The position of the centre of mass of the
The position of the centre of mass of the system: (Consider L=10 cm\mathrm{L}=10 \mathrm{~cm})

Options

  1. A2i^+3j^2 \hat{i}+3 \hat{j}
  2. B3i^+7j^3 \hat{i}+7 \hat{\mathrm{j}}
  3. C5i^+8j^5 \hat{\mathrm{i}}+8 \hat{\mathrm{j}}
  4. D4i^+9j^4 \hat{i}+9 \hat{j}

Correct answer

D. 4i^+9j^4 \hat{i}+9 \hat{j}

Step-by-step solution

A rod of length 5 L is bent right angle keeping one side length as 2 L. The position of the centre of mass of the
xcom=2 m(10)+3 m(0)5 m=4 cm\mathrm{x}_{\mathrm{com}}=\frac{2 \mathrm{~m}(10)+3 \mathrm{~m}(0)}{5 \mathrm{~m}}=4 \mathrm{~cm}
ycom=2 m(0)+3 m(15)5 m=9 cm\mathrm{y}_{\mathrm{com}}=\frac{2 \mathrm{~m}(0)+3 \mathrm{~m}(15)}{5 \mathrm{~m}}=9 \mathrm{~cm}
r→com=4i^+9j^\overrightarrow{\mathrm{r}}_{\mathrm{com}}=4 \hat{\mathrm{i}}+9 \hat{\mathrm{j}}
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