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The work functions of silver and sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is

Correct answer

1

Step-by-step solution

e v s = hv - hv 0 v s = h e v - h e v 0 ⇒ Slope is independent of stopping potential then ratio is 1 : 1.

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