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JEE Main 201325 AprilOnline
Exam
JEE Main
Year
2013
Date
25 April
Mode
Online
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2013 · 25 April · Online · Physics · Dual Nature of Matter

In an experiment on photoelectric effect, a student plots stopping...

In an experiment on photoelectric effect, a student plots stopping potential V0\mathrm{V}_0 against reciprocal of the wavelength λ\lambda of the incident light for two different metals A\mathrm{A} and B\mathrm{B}. These are shown in the figure. In an experiment on photoelectric effect, a student plots stopping potential V_0 against reciprocal of the wavelength λ
Looking at the graphs, you can most appropriately say that:

Options

  1. AWork function of metal B\mathrm{B} is greater than that of metal A\mathrm{A}
  2. BFor light of certain wavelength falling on both metal, maximum kinetic energy of electrons emitted from A will be greater than those emitted from B\mathrm{B}.
  3. CWork function of metal A\mathrm{A} is greater than that of metal B\mathrm{B}
  4. DStudents data is not correct

Correct answer

D. Students data is not correct

Step-by-step solution

hcλ−ϕ=eV0v0=hceλ−ϕe\begin{aligned} & \frac{\mathrm{hc}}{\lambda}-\phi=\mathrm{eV}_0 \\ & \mathrm{v}_0=\frac{\mathrm{hc}}{\mathrm{e} \lambda}-\frac{\phi}{\mathrm{e}} \end{aligned} In an experiment on photoelectric effect, a student plots stopping potential V_0 against reciprocal of the wavelength λ
As the value of 1λ\frac{1}{\lambda} (increasing and decreasing) is not specified hence we cannot say that which metal has comparatively greater or lesser work function (ϕ)(\phi).
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