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JEE Advanced2013PhysicsElectromagnetic InductionActual

Paragraph: A point charge Q is moving in a circular orbit of radius R in the x-y plane with an angular velocity . This can be considered as equivalent to a loop carrying a steady current Q 2 . A uniform magnetic field along the positive z -axis is now switched on, which increases at a constant rate from 0 to B in one second. Assume that the radius of the orbit remains constant. The application of the magnetic field i

Options

  1. ABR 4
  2. BBR 2
  3. CBR
  4. D2BR

Correct answer

B. BR 2

Step-by-step solution

∮ E.dl = - A dB dt E. 2 π R = - π R 2 B E = - BR 2 Alternate E 2 π R = - d ϕ dt = - π R 2 dB dt E = - R 2 dB dt = - BR 2

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