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JEE Advanced 2012Paper 1
Exam
JEE Advanced
Year
2012
Paper
Paper 1
Subject
Physics
Chapter
Electromagnetic Induction

JEE Advanced 2012 · Paper 1 · Physics · Electromagnetic Induction

A circular wire loop of radius R is placed in the x-y plane...

A circular wire loop of radius RR is placed in the x−yx-y plane centered at the origin OO. A square loop of side a(a<<R)a(a< < R) having two turns is placed with its centre at z=3Rz=\sqrt{3} R along the axis of the circular wire loop, as shown in figure.A circular wire loop of radius R is placed in the x-y plane centered at the origin O . A square loop of side a(a The
The plane of the square loop makes an angle of 45∘45^{\circ} with respect to the zz-axis. If the mutual inductance between the loops is given by μ0a22p/2R\frac{\mu_{0} a^{2}}{2^{p / 2} R}, then the value of pp is

Correct answer

0

Step-by-step solution

The magnetic field due to current carrying wire at the location of square loop is B=μ04π2πiR2(R2+3R2)3/2=μ0i16RB=\frac{\mu_{0}}{4 \pi} \frac{2 \pi i R^{2}}{\left(R^{2}+3 R^{2}\right)^{3 / 2}}=\frac{\mu_{0} i}{16 R} The mutual induction M=Nϕi=2i[μ0i16R×a2cos⁡45∘]∴M=μ0a2272R\begin{array}{l} M=\frac{N \phi}{i}=\frac{2}{i}\left[\frac{\mu_{0} i}{16 R} \times a^{2} \cos 45^{\circ}\right] \\ \therefore \quad M=\frac{\mu_{0} a^{2}}{2^{\frac{7}{2}} R} \end{array}
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