Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2025Paper 1
Exam
JEE Advanced
Year
2025
Paper
Paper 1
Subject
Physics
Chapter
Electrostatics

JEE Advanced 2025 · Paper 1 · Physics · Electrostatics

List-I shows four configurations, each consisting of a pair of...

List-I shows four configurations, each consisting of a pair of ideal electric dipoles. Each dipole has a dipole moment of magnitude pp, oriented as marked by arrows in the figures. In all the configurations the dipoles are fixed such that they are at a distance 2r2 r apart along the xx direction. The midpoint of the line joining the two dipoles is XX. The possible resultant electric fields E⃗\vec{E} at XX are given in List-II. Choose the option that describes the correct match between the entries in List-I to those in List-II.
List-I List-II
(P)(P) List-I shows four configurations, each consisting of a pair of ideal electric dipoles. Each dipole has a dipole moment
(1)(1) E⃗=0\vec{E}=0
(Q)(Q) List-I shows four configurations, each consisting of a pair of ideal electric dipoles. Each dipole has a dipole moment
(2)(2) E⃗=−p2πϵ0r3j^\vec{E}=-\frac{p}{2 \pi \epsilon_0 \mathrm{r}^3} \hat{\mathrm{j}}
(R)(R) List-I shows four configurations, each consisting of a pair of ideal electric dipoles. Each dipole has a dipole moment
(3)(3) E⃗=−p4πϵ0r3(i^−j^)\vec{E}=-\frac{p}{4 \pi \epsilon_0 \mathrm{r}^3}(\hat{\mathrm{i}}-\hat{\mathrm{j}})
(S)(S) List-I shows four configurations, each consisting of a pair of ideal electric dipoles. Each dipole has a dipole moment
(4)(4) E⃗=p4πϵ0r3(2i^−j^)\vec{E}=\frac{p}{4 \pi \epsilon_0 \mathrm{r}^3}(2 \hat{\mathrm{i}}-\hat{\mathrm{j}})
(5)(5) E⃗=pπϵ0r3i^\vec{E}=\frac{p}{\pi \epsilon_0 \mathrm{r}^3} \hat{\mathrm{i}}

Options

  1. AP→3,Q→1,R→2, S→4\mathrm{P} \rightarrow 3, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 2, \mathrm{~S} \rightarrow 4
  2. BP→4,Q→5,R→3, S→1\mathrm{P} \rightarrow 4, \mathrm{Q} \rightarrow 5, \mathrm{R} \rightarrow 3, \mathrm{~S} \rightarrow 1
  3. CP→2,Q→1,R→4, S→5\mathrm{P} \rightarrow 2, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 4, \mathrm{~S} \rightarrow 5
  4. DP→2,Q→1,R→3, S→5\mathrm{P} \rightarrow 2, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 3, \mathrm{~S} \rightarrow 5

Correct answer

C. P→2,Q→1,R→4, S→5\mathrm{P} \rightarrow 2, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 4, \mathrm{~S} \rightarrow 5

Step-by-step solution

Enet =−2kPr3j^Enet=−Pj^2πϵ0r3Enet=02Pi^4πϵ0r3−Pj^4πϵ0r3Enet=4kPi^r3P→2,Q→1,R→4,S→5E_{\text{net }}=\frac{-2 k P}{r^3} \hat{j} E_{n e t}=\frac{-P \hat{j}}{2 \pi \epsilon_0 r^3} \mathrm{E}_{\mathrm{net}}=0 \frac{2 \mathrm{P} \hat{\mathrm{i}}}{4 \pi \epsilon_0 \mathrm{r}^3}-\frac{\mathrm{P} \hat{\mathrm{j}}}{4 \pi \epsilon_0 \mathrm{r}^3} \mathrm{E}_{\mathrm{net}}=\frac{4 \mathrm{kP} \hat{\mathrm{i}}}{\mathrm{r}^3} \mathrm{P} \rightarrow 2, \mathrm{Q} \rightarrow 1, \mathrm{R} \rightarrow 4, \mathrm{ S} \rightarrow 5 Ans. (C)
Practice Electrostatics on Quantrex Academy →

More from Electrostatics

Two charges Q_1 = q and Q_2 = mq are placed at the points P_1(a, b) and P_2(ma, mb)… JEE Advanced 2026Consider an electric dipole comprising two charges +q and -q each with mass m , separated… JEE Advanced 2026Two point charges q_1=3\,μ C and q_2=-4\,μ C are placed at points (2 i +3 j +3 k ) and (… JEE Main 2026The electric potential as a function of x, y is given by V = 5(x^2 - y^2) V. The electric… JEE Main 2026A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb.… JEE Main 2026A three coulomb charge moves from the point (0, -2, -5) to the point (5, 1, 2) in an… JEE Main 2026A particle of charge q and mass m is projected from origin with an initial velocity v = (… JEE Main 2026A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an… JEE Main 2026 Full Electrostatics list All JEE Advanced PYQs