Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2024Paper 2
Exam
JEE Advanced
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Electrostatics

JEE Advanced 2024 · Paper 2 · Physics · Electrostatics

A small electric dipole p _0 , having a moment of inertia I about...

A small electric dipole p⃗0\vec{p}_0, having a moment of inertia II about its center, is kept at a distance rr from the center of a spherical shell of radius RR. The surface charge density σ\sigma is uniformly distributed on the spherical shell. The dipole is initially oriented at a small angle θ\theta as shown in the figure. While staying at a distance rr, the dipole is free to rotate about its center. A small electric dipole p _0 , having a moment of inertia I about its center, is kept at a distance r from the center If released from rest, then which of the following statement(s) is(are) correct? [ ε0\varepsilon_0 is the permittivity of free space.]

Options

  1. AThe dipole will undergo small oscillations at any finite value of rr.
  2. BThe dipole will undergo small oscillations at any finite value of r>Rr>R.
  3. CThe dipole will undergo small oscillations with an angular frequency of 2σp0ϵ0I\sqrt{\frac{2 \sigma p_0}{\epsilon_0 I}} at r=2Rr=2 R.
  4. DThe dipole will undergo small oscillations with an angular frequency of σp0100ϵ0I\sqrt{\frac{\sigma p_0}{100 \epsilon_0 I}} at r=10Rr=10 R.

Correct answer

B. The dipole will undergo small oscillations at any finite value of r>Rr>R.

Step-by-step solution

A small electric dipole p _0 , having a moment of inertia I about its center, is kept at a distance r from the center τ=∣p⃗×E⃗∣Iα=p0Esin⁡θα=p⋅θI(14πε0σ4πR2r2)α=(p0σR2Iε0r2)⋅θ∴ω=p0σR2Iε0r2\begin{aligned} & \tau=|\vec{p} \times \vec{E}| \\ & I \alpha=p_0 E \sin \theta \\ & \alpha=\frac{p \cdot \theta}{I}\left(\frac{1}{4 \pi \varepsilon_0} \frac{\sigma 4 \pi R^2}{r^2}\right) \\ & \alpha=\left(\frac{p 0 \sigma R^2}{I \varepsilon_0 r^2}\right) \cdot \theta \\ & \therefore \omega=\sqrt{\frac{p 0 \sigma R^2}{I \varepsilon_0 r^2}} \end{aligned})ForForr=2Rr=2 R (\omega=\sqrt{\frac{p_0 \sigma}{4 / \varepsilon_0}} \quad(\mathrm{C}) is incorrect )) Also, for r=10Rr=10 R (\omega=\sqrt{\frac{p_0 \sigma}{4 l(100)}}) (D is correct) It will oscillate for any finite value of r>Rr>R. (B is correct)$
Practice Electrostatics on Quantrex Academy →

More from Electrostatics

Two charges Q_1 = q and Q_2 = mq are placed at the points P_1(a, b) and P_2(ma, mb)… JEE Advanced 2026Consider an electric dipole comprising two charges +q and -q each with mass m , separated… JEE Advanced 2026Two point charges q_1=3\,μ C and q_2=-4\,μ C are placed at points (2 i +3 j +3 k ) and (… JEE Main 2026The electric potential as a function of x, y is given by V = 5(x^2 - y^2) V. The electric… JEE Main 2026A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb.… JEE Main 2026A three coulomb charge moves from the point (0, -2, -5) to the point (5, 1, 2) in an… JEE Main 2026A particle of charge q and mass m is projected from origin with an initial velocity v = (… JEE Main 2026A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an… JEE Main 2026 Full Electrostatics list All JEE Advanced PYQs