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Consider an electric field E =E₀ x where E ₀ is a constant. The flux through the shaded area ( as shown in the figure) due to this field is

Options

  1. A2 E₀ a^2
  2. B2 E₀ a^2
  3. CE₀ a^2
  4. DE₀ a^2 2

Correct answer

C. E₀ a^2

Step-by-step solution

Electric flux, E S , or =E S Here, is the angle between E and S . In this question =45^ , because S is perpendicular to the surface. gathered E=E₀ S=( 2 a )(a)= 2 a^2 = (E₀ ) ( 2 a^2 ) 45^ =E₀ a^2 gathered Correct option is (c). Analysis of Question (i) Question is moderately tough. (ii) The given shaded area is a rectangle not a square. One side of this rectangle is a and other side is 2 a . (iii) Electric field is uniform, whose magnitude is E₀ and direction is positive x . In uniform electric field we can use, =

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