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JEE Advanced2010PhysicsElectrostaticsActual

A few electric field lines for a system of two charges Q₁ and Q₂ fixed at two different points on the x -axis are shown in the figure. These lines suggest that

Options

  1. A|Q₁ |> |Q₂ |
  2. B|Q₁ | < |Q₂ |
  3. Cat a finite distance to the left of Q₁ the electric field is zero
  4. Dat a finite distance to the right of Q₂ the electric field is zero

Correct answer

A. |Q₁ |> |Q₂ |

Step-by-step solution

From the behaviour of electric lines, we can say that Q₁ is positive and Q₂ is negative. Further, |Q₁ |> |Q₂ | At some finite distance to the right of Q₂ , electric field will be zero. Because electric field due to Q₁ is towards right (away from Q₁ ) and due to Q₂ is towards left (towards Q₂ ). But since magnitude of Q₁ is more, the two fields may cancel each other because distance of that point from Q₁ will also be more. The correct options are (a) and (d).

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