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JEE Advanced2025PhysicsGravitationActual

A geostationary satellite above the equator is orbiting around the earth at a fixed distance r₁ from the center of the earth. A second satellite is orbiting in the equatorial plane in the opposite direction to the earth's rotation, at a distance r₂ from the center of the earth, such that r₁=1.21 r₂ . The time period of the second satellite as measured from the geostationary satellite is 24 p hours. The value of p is

Correct answer

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Step-by-step solution

T r ^ 3 / 2 T ₂ ~T ₁ = ( r ₂ r ₁ )^ 3 / 2 ₂ ₁ = ( r₁ r₂ )^ 3 / 2 =(1.21)^ 3 / 2 aligned & ₂= ₁(1.331) ...(i) & ( ₂+ ₁ ) t₀=2 ...(ii) aligned t₀= 2 ₂+ ₁ = 2 ( 4 3 +1 ) ₁ = 6 7 ₁ t ₀= 6 2 ( ~T _ GSS ) (7) t ₀= 3 24 hours 7 = 24 p hours p = 7 3 =2.33

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