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JEE Advanced 2021Paper 2
Exam
JEE Advanced
Year
2021
Paper
Paper 2
Subject
Physics
Chapter
Gravitation

JEE Advanced 2021 · Paper 2 · Physics · Gravitation

The distance between two stars of masses 3 M _ S and 6 M _ S is 9R...

The distance between two stars of masses 3MS3{M}_{S} and 6MS6{M}_{S} is 9R9R. Here RR is the mean distance between the centres of the Earth and the Sun, and MS{M}_{S} is the mass of the Sun. Two stars orbit around their common centre of mass in circular orbits with period nTnT, where TT is the period of Earth's revolution around the Sun.

The value of nn is _____.

Correct answer

0

Step-by-step solution

T=2πR3/2GMST = \dfrac{2\pi{R}^{3 / 2}}{\sqrt{G{M}_{S}}}

For binary stars,

T′=2πr3/2G(M1+M2)T ' = \dfrac{2\pi{r}^{3 / 2}}{\sqrt{G\left({M}_{1} + {M}_{2}\right)}}

Put M1=3MS{M}_{1} = 3{M}_{S},M2=6MS{M}_{2} = 6{M}_{S} and r=9Rr = 9R

T′=2π×93/2×R3/2G(3MS+6MS)=2π×93/2×R3/291/2GMS=9(2πR3/2GMS)T ' = \dfrac{2\pi \times {9}^{3 / 2} \times {R}^{3 / 2}}{\sqrt{G\left(3{M}_{S} + 6{M}_{S}\right)}} = \dfrac{2\pi \times {9}^{3 / 2} \times {R}^{3 / 2}}{{9}^{1 / 2}\sqrt{G{M}_{S}}} = 9\left(\dfrac{2\pi{R}^{3 / 2}}{\sqrt{G{M}_{S}}}\right)

∴T′=9T∴ T ' = 9T

Value of n=9n = 9.

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