JEE Advanced2012PhysicsLaws of MotionActual
Two large vertical and parallel metal plates having a separation of 1 ~cm are connected to a DC voltage source of potential difference X . A proton is released at rest midway between the two plates. It is found to move at 45^ to the vertical JUST after release. Then X is nearly
Options
- A1 10⁻⁵ ~V
- B1 10⁻⁷ V
- C1 10⁻⁹ V
- D1 10⁻¹⁰ V
Correct answer
C. 1 10⁻⁹ V
Step-by-step solution
According to the question, a proton is released at rest mid-way between the two plates and is found to move at 45^ , so net force is at 45^ from vertical and two forces acting on the proton just after the release are as shown in the figure. q E=m g V= m g d q = 1.67 10⁻²⁷ 10 10⁻² 1.6 10⁻¹⁹ =10⁻⁹ ~V