JEE Main2013PhysicsLaws of MotionActual
A uniform cylinder of length L and mass M having cross-sectional area A is suspended, with its length vertical, from a fixed point by a massless spring, such that it is half submerged in a liquid of density σ at equilibrium position. The extension x 0 of the spring when it is in equilibrium is :
Options
- AMg k 1 - LA σ 2 M
- BMg k 1 + LA σ M
- CMg k
- DMg k 1 - LA σ M
Correct answer
A. Mg k 1 - LA σ 2 M
Step-by-step solution
kx 0 + F B = mg kx 0 + σ L 2 Ag = Mg x 0 = Mg - σ LAg 2 k = Mg k 1 - σ LA 2 M