JEE Advanced2007PhysicsLaws of MotionActual
Two particles of mass m each are tied at the ends of a light string of length 2 a . The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance a from the centre P (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force F . As a result, the particles move towards each other on the surface. T
Options
- AF 2 m a a^2-x^2
- BF 2 m x a^2-x^2
- CF 2 m x a
- DF 2 m a^2-x^2 x
Correct answer
B. F 2 m x a^2-x^2
Step-by-step solution
6. aligned & 2 T =F & T= F 2 & Acceleration of particle = T m = F 2 m = F 2 m x a^2-x^2 aligned Option (b) is correct.