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JEE Main 2007
Exam
JEE Main
Year
2007
Subject
Physics
Chapter
Laws of Motion

JEE Main 2007 · Physics · Laws of Motion

A block of mass ' m ' is connected to another block of mass ' M '...

A block of mass ' m\mathrm{m} ' is connected to another block of mass ' M\mathrm{M} ' by a spring (massless) of spring constant ' k\mathrm{k} '. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force 'F\mathrm{F}' starts acting on the block of mass 'M\mathrm{M}' to pull it. Find the force on the block of mass 'm\mathrm{m}'

Options

  1. AmFM\frac{\mathrm{mF}}{\mathrm{M}}
  2. B(M+m)Fm\frac{\mathrm{(M+m) F}}{\mathrm{m}}
  3. CmF(m+M)\frac{\mathrm{m F}}{\mathrm{(m+M)}}
  4. DMF(m+M)\frac{\mathrm{MF}}{(\mathrm{m}+\mathrm{M})}

Correct answer

C. mF(m+M)\frac{\mathrm{m F}}{\mathrm{(m+M)}}

Step-by-step solution

Kx=ma=mFm+M\mathrm{Kx}=\mathrm{ma}=\frac{\mathrm{mF}}{\mathrm{m}+\mathrm{M}}
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