JEE Main2007PhysicsLaws of MotionActual
A block of mass ' m ' is connected to another block of mass ' M ' by a spring (massless) of spring constant ' k '. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force ' F ' starts acting on the block of mass ' M ' to pull it. Find the force on the block of mass ' m '
Options
- AmF M
- B(M+m) F m
- Cm F (m+M)
- DMF ( m + M )
Correct answer
C. m F (m+M)
Step-by-step solution
Kx = ma = mF m + M