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JEE Advanced2006PhysicsLaws of MotionActual

A circular disc with a groove along its diameter is placed horizontally. A block of mass 1 ~kg is placed as shown. The coefficient of friction between the block and all surfaces of groove in contact is =2 / 5 . The disc has an acceleration of 25 ~m / s ^2 . Find the acceleration of the block with respect to disc.

Correct answer

10

Step-by-step solution

Normal reaction in vertical direction N₁=m g Normal reaction from side to the groove N₂=m a 37^ Therefore, acceleration of block with respect to discs a_r= m a 37^ - N₁- N₂ m Substituting the values we get, a_r=10 ~m / s ^2

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