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JEE Advanced 2017Paper 1
Exam
JEE Advanced
Year
2017
Paper
Paper 1
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Advanced 2017 · Paper 1 · Physics · Magnetic Effects of Current

A charged particle is introduced at the origin x = 0, y = 0, z = 0...

A charged particle is introduced at the origin x=0,y=0,z=0x = 0, y = 0, z = 0 with a given initial velocity v→\overset{\to}{v} . A uniform electric field E→\overset{\to}{E} and a uniform magnetic field B→\overset{\to}{B} exist everywhere. The velocity v→\overset{\to}{v} , electric field E→\overset{\to}{E} and a uniform magnetic field B→\overset{\to}{B} are given in the columns below
Column 1 Column 2 Column 3
1. Electron with \overset{\to}{v} = 2\dfrac{{E}_{0}}{{B}_{0}}\overset{^}{x} (i) \overset{\to}{E} = {E}_{0}\overset{^}{z} (P) \overset{\to}{B} = - {B}_{0}\overset{^}{x}
2. Electron with \overset{\to}{v} = 2\dfrac{{E}_{0}}{{B}_{0}}\overset{^}{y} (ii) \overset{\to}{E} = - {E}_{0}\overset{^}{y} (Q) \overset{\to}{B} = {B}_{0}\overset{^}{x}
3.Proton with v→\overset{\to}{v} =0 (iii) \overset{\to}{E} = {- E}_{0}\overset{^}{x} (R) \overset{\to}{B} = - {B}_{0}\overset{^}{y}
4. Proton with \overset{\to}{v} = 2\dfrac{{E}_{0}}{{B}_{0}}\overset{^}{x} (iv) \overset{\to}{E} = {E}_{0}\overset{^}{x} (S) \overset{\to}{B} = - {B}_{0}\overset{^}{z}
In which case would the particle move in a straight line along the negative direction of y axis

Options

  1. A(4)(ii)(S)( 4 ) ( ii ) ( S )
  2. B(3)(ii)(P)( 3 ) ( ii ) ( P )
  3. C(2)(iii)(Q)( 2 ) ( iii ) ( Q )
  4. D(3)(ii)(R)( 3 ) ( ii ) ( R )

Correct answer

D. (3)(ii)(R)( 3 ) ( ii ) ( R )

Step-by-step solution

For particle to move in -ve y-direction, either its velocity must be in –ve y-direction (if initial velocity ≠\ne0) and force should be parallel to velocity or it must experience a net force in –ve y-direction only (if initial velocity = 0)
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