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JEE Advanced 2014Paper 1
Exam
JEE Advanced
Year
2014
Paper
Paper 1
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Advanced 2014 · Paper 1 · Physics · Magnetic Effects of Current

Two parallel wires in the plane of the paper are distance X _ 0...

Two parallel wires in the plane of the paper are distance X0{X}_{0} apart. A point charge is moving with speed u between the wires in the same plane at a distance X1{X}_{1} from one of the wires. When the wires carry current of magnitude II in the same direction, the radius of curvature of the path of the point charge is R1{R}_{1} . In contrast, if the currents II in the two wires have directions opposite to each other, the radius of curvature of the path is R2{R}_{2} . If X0X1=3\dfrac{{X}_{0}}{{X}_{1}} = 3 , value of R1R2\dfrac{{R}_{1}}{{R}_{2}} isTwo parallel wires in the plane of the paper are distance X _ 0 apart. A point charge is moving with speed u betweenTwo parallel wires in the plane of the paper are distance X _ 0 apart. A point charge is moving with speed u between

Correct answer

3

Step-by-step solution

Two parallel wires in the plane of the paper are distance X _ 0 apart. A point charge is moving with speed u between
B1=12(μ02π)(3Ix0){B}_{1} = \dfrac{1}{2}\left(\dfrac{{\mu}_{0}}{2\pi}\right)\left(\dfrac{3I}{{x}_{0}}\right)
R1=mvqB1{R}_{1} = \dfrac{mv}{q{B}_{1}}
Two parallel wires in the plane of the paper are distance X _ 0 apart. A point charge is moving with speed u between
R2=mvqB2{R}_{2} = \dfrac{mv}{q{B}_{2}}
⇒R1R2=B2B1=1319=3⇒ \dfrac{{R}_{1}}{{R}_{2}} = \dfrac{{B}_{2}}{{B}_{1}} = \dfrac{\dfrac{1}{3}}{\dfrac{1}{9}} = 3
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