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JEE Advanced 2013Paper 2
Exam
JEE Advanced
Year
2013
Paper
Paper 2
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Advanced 2013 · Paper 2 · Physics · Magnetic Effects of Current

A steady current I flows along an infinitely long hollow...

A steady current II flows along an infinitely long hollow cylindrical conductor of radius RR. This cylinder is placed co-axially inside an infinite solenoid of radius 2R2R. The solenoid has nn turns per unit length and carries a steady current II. Consider a point PP at a distance rr from the common axis. The correct statement(s) is(are):A steady current I flows along an infinitely long hollow cylindrical conductor of radius R . This cylinder is placed

Options

  1. AIn the region 0<r<R0 < r < R, the magnetic field is non-zero.
  2. BIn the region R<r<2RR < r < 2R, the magnetic field is along the common axis.
  3. CIn the region R<r<2RR < r < 2R, the magnetic field is tangential to the circle of radius rr, centered on the axis.
  4. DIn the region r>2R,r > 2R, the magnetic field is non-zero.

Correct answer

A. In the region 0<r<R0 < r < R, the magnetic field is non-zero.

Step-by-step solution

A steady current I flows along an infinitely long hollow cylindrical conductor of radius R . This cylinder is placed

If we consider a point at a distance rr from a common axis such that 0<r<R0 < r < R, the magnetic field is non-zero because inside infinite solenoid magnetic field is, B→=μ0ni\overset{\to}{B} = {\mu}_{0}ni and due to the hollow cylinder it is zero. Hence, net magnetic field is non-zero.

If 2R<r2R < r, then magnetic field due to an infinite solenoid is zero but there will be a non-zero magnetic field because of hollow cylinder. Hence, net magnetic field is non-zero.

If R<r<2RR < r < 2R, then the magnetic field due to solenoid is along the axis and magnetic field due to the hollow cylinder is in circular form. Hence, the net magnetic field is neither along axis nor in tangential direction.

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