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JEE Advanced 2010Paper 1
Exam
JEE Advanced
Year
2010
Paper
Paper 1
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Advanced 2010 · Paper 1 · Physics · Magnetic Effects of Current

A thin flexible wire of length L is connected to two adjacent fixed...

A thin flexible wire of length LL is connected to two adjacent fixed points and carries a current II in the clockwise direction, as shown in the figure. When the system is put in a uniform magnetic field of strength BB going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is A thin flexible wire of length L is connected to two adjacent fixed points and carries a current I in the clockwise

Options

  1. AIBLI B L
  2. BIBLπ\frac{I B L}{\pi}
  3. CIBL2π\frac{I B L}{2 \pi}
  4. DIBL4π\frac{I B L}{4 \pi}

Correct answer

C. IBL2π\frac{I B L}{2 \pi}

Step-by-step solution

A thin flexible wire of length L is connected to two adjacent fixed points and carries a current I in the clockwise
L=2πRR=L2π2Tsin⁡(dθ)=FmL=2 \pi RR=\frac{L}{2 \pi}2 T \sin (d \theta)=F_m for small angles, sin⁡(dθ)≈dθ\sin (d \theta) \approx d \theta∴2T(dθ)=I(dL)Bsin⁡90∘=I(2R\cdotdθ)\cdotB∴T=IRB=ILB2π\begin{aligned} \therefore \quad2 T(d \theta)& =I(d L) B \sin 90^{{}^{\circ}} \\ & =I(2 R \cdotd \theta) \cdotB \\ \therefore \quad T & =I R B=\frac{I L B}{2 \pi} \end{aligned}∴\therefore correct option is (c)
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