JEE Advanced2010PhysicsMathematics in PhysicsActual
A student uses a simple pendulum of exactly 1 ~m length to determine g , the acceleration due to gravity. He uses a stop watch with the least count of 1 ~s for this and records 40 ~s for 20 oscillations. For this observation, which of the following statement(s) is/are true?
Options
- AError T in measuring T , the time period, is 0.05 ~s
- BError T in measuring T , the time period, is 1 ~s
- CPercentage error in the determination of g is 5 %
- DPercentage error in the determination of g is 2.5 %
Correct answer
A. Error T in measuring T , the time period, is 0.05 ~s
Step-by-step solution
T= 40 ~s 20 =2 ~s . Further, t=n T=20 T or t=20 T t t = T T or T= T t t= ( 2 40 )(1)=0.05 ~s Further, T=2 l g or T g^ -1 / 2 T T 100=- 1 2 g g 100 or % error in determination of g is aligned g g 100 & =-200 T T & =- 200 0.05 2 =-5 % aligned correct options are (a) and (c).