Two solid spheres A and B of equal volumes but of different densities d_A and d_B are connected by a string. They are fully immersed in a fluid of density d_F . They get arranged into an equilibrium state as shown in the figure with a tensi

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Two solid spheres A and B of equal volumes but of different densities d_A and d_B are connected by a string. They are fully immersed in a fluid of density d_F . They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if

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Correct answer: A. d_A < d_F

Equilibrium of A aligned V d_F g & =T+W_A & =T+V d_A g aligned Equilibrium of B , T+V d_F g=V d_B g Adding Eqs. (i) and (ii), we get 2 d_f=d_A+d_B Option (d) is correct. From Eq. (i), we can see that d_F>d_A [as T>0 ] Option (a) is correct. From Eq. (ii) we can see that, d_B>d_F Option (a) is correct. Correct options are (a), (b) and (d). Analysis of Question Question is moderately difficult but conceptwise it is good.

Two solid spheres A and B of equal volumes but of different densities d_A and d_B are connected by a string. They are fully immersed in a fluid of density d_F . They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if

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