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JEE Advanced 2009Paper 2
Exam
JEE Advanced
Year
2009
Paper
Paper 2
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Advanced 2009 · Paper 2 · Physics · Mechanical Properties of Fluids

A cylindrical vessel of height 500 ~mm has an orifice (small hole)...

A cylindrical vessel of height 500 mm500 \mathrm{~mm} has an orifice (small hole) at its bottom. The orifice is initially closed and water is filled in it upto height HH. Now the top is completely sealed with a cap and the orifice at the bottom is opened. Some water comes out from the orifice and the water level in the vessel becomes steady with height of water column being 200 mm\mathrm{mm}. Find the fall in height (in mm\mathrm{mm} ) of water level due to opening of the orifice. [Take atmospheric pressure =1.0×105Nm−2=1.0 \times 10^5 \mathrm{Nm}^{-2}, density of water =1000 kg m−3=1000 \mathrm{~kg} \mathrm{~m}^{-3} and g=10g=10 ms−2\mathrm{ms}^{-2}. Neglect any effect of surface tension.]A cylindrical vessel of height 500 ~mm has an orifice (small hole) at its bottom. The orifice is initially closed andA cylindrical vessel of height 500 ~mm has an orifice (small hole) at its bottom. The orifice is initially closed and

Correct answer

6

Step-by-step solution

In this question we will have to assume that temperature of enclosed air about water is constant (or pV=p V= constant) A cylindrical vessel of height 500 ~mm has an orifice (small hole) at its bottom. The orifice is initially closed and
p=p0−ρghp0[A(500−H)]=p[A(200)]Solvingthesetwoequations,weget\begin{gathered}p=p_0-\rho g h \\ p_0[A(500-H)]=p[A(200)] \end{gathered} Solving these two equations, we getH=206 mm∴ Level fall =(206−200)mm=6 mm\begin{aligned}H & =206 \mathrm{~mm}\\ \therefore \quad \text{ Level fall }& =(206-200) \mathrm{mm}\\ & =6 \mathrm{~mm} \end{aligned}$
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