JEE Advanced2010PhysicsMechanical Properties of SolidsActual
A 0.1 ~kg mass is suspended from a wire of negligible mass. The length of the wire is 1 ~m and its cross-sectional area is 4.9 10⁻⁷ ~m ^2 . If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency 140 rad s ⁻¹ . If the Young's modulus of the material of the wire is n 10^9 Nm ⁻² , the value of n is
Correct answer
0
Step-by-step solution
= K m = Y A l m = (n 10^9 ) (4.9 10⁻⁷ ) 1 0.1 Putting, =140 rad s ⁻¹ in above equation we get, n=4 Answer is 4 .