JEE Main 20266 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 6 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Mechanical Properties of Solids
JEE Main 2026 · 6 April · Morning Shift · Physics · Mechanical Properties of Solids
A lift of mass 1600 kg is supported by thick iron wire. If the...
A lift of mass kg is supported by thick iron wire. If the maximum stress which the wire can withstand is N/m and its radius is mm, then maximum acceleration the lift can take is _______ m/s. (take m/s and )
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Maximum stress \sigma_\max = 4 \times 10^8 N/m
Radius of wire m
Mass of lift kg
Maximum tension the wire can withstand is given by:
T_\max = \sigma_\max \times \pi r^2
T_\max = 4 \times 10^8 \times 3.14 \times (4 \times 10^{-3})^2
T_\max = 4 \times 10^8 \times 3.14 \times 16 \times 10^{-6} = 20096 N
When the lift accelerates upwards with maximum acceleration , the tension in the wire is:
T_\max = m(g + a)
m/s
Answer:
Radius of wire m
Mass of lift kg
Maximum tension the wire can withstand is given by:
T_\max = \sigma_\max \times \pi r^2
T_\max = 4 \times 10^8 \times 3.14 \times (4 \times 10^{-3})^2
T_\max = 4 \times 10^8 \times 3.14 \times 16 \times 10^{-6} = 20096 N
When the lift accelerates upwards with maximum acceleration , the tension in the wire is:
T_\max = m(g + a)
m/s
Answer: