JEE Advanced 2019Paper 2
- Exam
- JEE Advanced
- Year
- 2019
- Paper
- Paper 2
- Subject
- Physics
- Chapter
- Motion in Two Dimensions
JEE Advanced 2019 · Paper 2 · Physics · Motion in Two Dimensions
A ball is thrown from ground at an angle θ with horizontal and with...
A ball is thrown from ground at an angle with horizontal and with an initial speed For the resulting projectile motion, the magnitude of average velocity of the ball up to the point when it hits the ground for the first time is After hitting the ground, ball rebounds at the same angle but with a reduced speed of Its motion continues for a long time as shown in figure. If the magnitude of average velocity of the ball for entire duration of motion is the value of is______
Correct answer
0
Step-by-step solution
For first projectile
Average velocity, \left(V\right) = \dfrac{R}{T} = {U}_{x} = {V}_{1}\left(\right)
For journey
⇒ {U}_{x}\left(\dfrac{1 + \dfrac{1}{{\alpha}^{2}} + \dfrac{1}{{\alpha}^{4}} + \ldots \dfrac{1}{{\alpha}^{2n}}}{1 + \dfrac{1}{\alpha} + \dfrac{1}{{\alpha}^{2}} + \ldots + \dfrac{1}{{\alpha}^{n}}}\right) = 0.8{v}_{1}, \left(\right)
Average velocity, \left(V\right) = \dfrac{R}{T} = {U}_{x} = {V}_{1}\left(\right)
For journey
⇒ {U}_{x}\left(\dfrac{1 + \dfrac{1}{{\alpha}^{2}} + \dfrac{1}{{\alpha}^{4}} + \ldots \dfrac{1}{{\alpha}^{2n}}}{1 + \dfrac{1}{\alpha} + \dfrac{1}{{\alpha}^{2}} + \ldots + \dfrac{1}{{\alpha}^{n}}}\right) = 0.8{v}_{1}, \left(\right)