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JEE Advanced 2008Paper 2
Exam
JEE Advanced
Year
2008
Paper
Paper 2
Subject
Physics
Chapter
Motion in Two Dimensions

JEE Advanced 2008 · Paper 2 · Physics · Motion in Two Dimensions

A bob of mass M is suspended by a massless string of length L . The...

A bob of mass MM is suspended by a massless string of length LL. The horizontal velocity vv at position AA is just sufficient to make it reach the point BB. The angle θ\theta at which the speed of the bob is half of that at AA, satisfies A bob of mass M is suspended by a massless string of length L . The horizontal velocity v at position A is just

Options

  1. Aθ=π4\theta=\frac{\pi}{4}
  2. Bπ4<θ<π2\frac{\pi}{4} < \theta < \frac{\pi}{2}
  3. Cπ2<θ<3π4\frac{\pi}{2} < \theta < \frac{3 \pi}{4}
  4. D3π4<θ<π\frac{3 \pi}{4} < \theta < \pi

Correct answer

D. 3π4<θ<π\frac{3 \pi}{4} < \theta < \pi

Step-by-step solution

v=5gLSolvingEqs.(i),(ii)v=\sqrt{5 g L}Solving Eqs. (i), (ii) and (iii) we get, \cos \theta=-78\frac{7}{8} \quad  or  θ=\text{\text{ or } } \theta=\cos ^{-1}\left(- \frac{7}{8}\right)=151^{\circ} ∴\therefore correct option is (d).
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