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JEE Advanced 2018Paper 2
Exam
JEE Advanced
Year
2018
Paper
Paper 2
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2018 · Paper 2 · Physics · Ray Optics

A wire is bent in the shape of a right angled triangle and is...

A wire is bent in the shape of a right angled triangle and is placed in front of a concave mirror of focal length ff , as shown in the figure. Which of the figures shown in the four options qualitatively represent(s) the shape of the image of the bent wire? (These figures are not to scale.) A wire is bent in the shape of a right angled triangle and is placed in front of a concave mirror of focal length f ,

Options

  1. AWhat is essential for the normal rate of hormone synthesis in the thyroid?
  2. BWhat is essential for the normal rate of hormone synthesis in the thyroid?
  3. CWhat is essential for the normal rate of hormone synthesis in the thyroid?
  4. DWhat is essential for the normal rate of hormone synthesis in the thyroid?

Correct answer

D. What is essential for the normal rate of hormone synthesis in the thyroid?

Step-by-step solution

A wire is bent in the shape of a right angled triangle and is placed in front of a concave mirror of focal length f ,
Distance of point A is f2\dfrac{f}{2}
Let A' is the image of A from mirror, for this image
1v+1−f2=1−f\dfrac{1}{v} + \dfrac{1}{- \dfrac{f}{2}} = \dfrac{1}{- f}
1v=2f=1f=1f\dfrac{1}{v} = \dfrac{2}{f} = \dfrac{1}{f} = \dfrac{1}{f}
Image of line AB should be perpendicular to the principle axis and image of F will form at infinity, therefor correct image diagram is
A wire is bent in the shape of a right angled triangle and is placed in front of a concave mirror of focal length f ,
A wire is bent in the shape of a right angled triangle and is placed in front of a concave mirror of focal length f ,
ff−u=h2h1\dfrac{f}{f - u} = \dfrac{{h}_{2}}{{h}_{1}}
h2=−f(f−x)−f+x{h}_{2} = \dfrac{- f\left(f - x\right)}{- f + x}
h2=f{h}_{2} = f
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