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JEE Advanced 2007Paper 2
Exam
JEE Advanced
Year
2007
Paper
Paper 2
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2007 · Paper 2 · Physics · Ray Optics

Paragraph: The figure shows a surface X Y separating two...

Paragraph: The figure shows a surface XYX Y separating two transparent media, medium-1 and medium-2. The lines aba b and cdc d represent wavefronts of a light wave travelling in medium-1 and incident on XYX Y. The lines ef and ghg h represent wavefronts of the light wave in medium-2 after refraction.Paragraph: The figure shows a surface X Y separating two transparent media, medium-1 and medium-2. The lines a b and c
Question: The phases of the light wave at c,d,ec, d, e and ff are ϕc,ϕd,ϕe\phi_c, \phi_d, \phi_e and ϕf\phi_f, respectively. It is given that ϕc≠ϕf\phi_c \neq \phi_f.

Options

  1. Aϕc\phi_c cannot be equal to ϕd\phi_d
  2. Bϕd\phi_d can be equal to ϕe\phi_e
  3. C(ϕd−ϕf)\left(\phi_d-\phi_f\right) is equal to (ϕc−ϕe)\left(\phi_c-\phi_e\right)
  4. D(ϕd−ϕc)\left(\phi_d-\phi_c\right) is not equal to (ϕf−ϕe)\left(\phi_f-\phi_e\right)

Correct answer

C. (ϕd−ϕf)\left(\phi_d-\phi_f\right) is equal to (ϕc−ϕe)\left(\phi_c-\phi_e\right)

Step-by-step solution

All points on a wavefront are at the same phase. ∴ϕd=ϕc and ϕf=ϕe∴ϕd−ϕf=ϕc−ϕe\begin{array}{rlrl} \therefore & \phi_d & =\phi_c \text{ and } \phi_f=\phi_e \\ & \therefore & \phi_d-\phi_f & =\phi_c-\phi_e \end{array} Hence, the correct option is (c).
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