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JEE Advanced 2006
Exam
JEE Advanced
Year
2006
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2006 · Physics · Ray Optics

A point object is placed at distance of 20 ~cm from a thin...

A point object is placed at distance of 20 cm20 \mathrm{~cm} from a thin planoconvex lens of focal length 15 cm15 \mathrm{~cm}. The plane surface of the lens is now silvered. The image created by the system is at A point object is placed at distance of 20 ~cm from a thin planoconvex lens of focal length 15 ~cm . The plane surface

Options

  1. A60 cm60 \mathrm{~cm} to the left of the system
  2. B60 cm60 \mathrm{~cm} to the right of the system
  3. C12 cm12 \mathrm{~cm} to the left of the system
  4. D12 cm12 \mathrm{~cm} to the right of the system

Correct answer

C. 12 cm12 \mathrm{~cm} to the left of the system

Step-by-step solution

Refraction from lens 1v1−1−20=115v=60cm\begin{aligned}\frac{1}{v_1}-\frac{1}{-20}& =\frac{1}{15}\\ v & =60 \mathrm{ cm} \end{aligned}A point object is placed at distance of 20 ~cm from a thin planoconvex lens of focal length 15 ~cm . The plane surfacei.e.,firstimageisformedat\\ i.e., first image is formed at60 \mathrm{ cm}totherightoflenssystem.ReflectionfrommirrorAfterreflectionfromthemirror,thesecondimagewillbeformedatadistanceofto the right of lens system. Reflection from mirror After reflection from the mirror, the second image will be formed at a distance of60 \mathrm{ cm}totheleftoflenssystem.Refractionfromlensto the left of lens system. Refraction from lens1v3−160=115v3=12cm\begin{aligned}\frac{1}{v_3}-\frac{1}{60}& =\frac{1}{15}\\ v_3 & =12 \mathrm{ cm} \end{aligned}$A point object is placed at distance of 20 ~cm from a thin planoconvex lens of focal length 15 ~cm . The plane surface
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