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JEE Advanced 2017Paper 2
Exam
JEE Advanced
Year
2017
Paper
Paper 2
Subject
Physics
Chapter
Wave Optics

JEE Advanced 2017 · Paper 2 · Physics · Wave Optics

Two coherent monochromatic point sources S _ 1 and S _ 2 of...

Two coherent monochromatic point sources S1{S}_{1} and S2{S}_{2} of wavelength λ=600nm\lambda = 600nm are placed symmetrically on either side of the center of the circle as shown. The sources are separated by a distance d=1.8mm.d = 1.8mm . This arrangement produces interference fringes visible as alternate bright and dark spots on the circumference of the circle. The angular separation between two consecutive bright spots is Δθ\Delta\theta . Which of the following options is/are correct?
Two coherent monochromatic point sources S _ 1 and S _ 2 of wavelength λ = 600nm are placed symmetrically on either

Options

  1. AA dark spot will be formed at the point P2{P}_{2}
  2. BThe angular separation between two consecutive bright spots decreases as we move from P1{P}_{1} to P2{P}_{2} along the first quadrant
  3. CAt P2{P}_{2} the order of the fringe will be maximum
  4. DThe total number of fringes produced between P1{P}_{1} and P2{P}_{2} in the first quadrant is close to 3000

Correct answer

C. At P2{P}_{2} the order of the fringe will be maximum

Step-by-step solution

At point P2;{P}_{2};

\Deltax=d=1.8mm=3000λ\Deltax = d = 1.8mm = 3000\lambda

Hence a (bright fringe) will be formed at P2{P}_{2}

Now \Deltax=dcosθ=nλ\Deltax = dcos \theta = n\lambda

cosθ=nλdcos \theta = \dfrac{n\lambda}{d}, θ\theta is with the x−axisx - axis.

−sinθΔθ=(\Deltan)λd- sin\theta\Delta\theta = \left(\Deltan\right)\dfrac{\lambda}{d}

Δθ=−(\Deltan)λdsinθ\Delta\theta = - \left(\Deltan\right)\dfrac{\lambda}{dsin \theta}

Δθ\Delta\theta increases as θ\theta decreases

At P2,{P}_{2}, the order of fringe will be maximum.

For total no. of bright fringes d=nλ⇒n=3000d = n\lambda ⇒ n = 3000

∴∴ total no. of fringes =3000= 3000

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