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A Young's double slit interference arrangement with slits S 1 and S 2 is immersed in water (refractive index = 4 3 ) as shown in the figure. The positions of maxima on the surface of water are given by x 2 = p 2 m 2 λ 2 - d 2 , where λ is the wavelength of light in air (refractive index = 1), 2 d is the separation between the slits and m is an integer. The value of p is

Correct answer

0

Step-by-step solution

x 1 = x 2 + d 2 x 2 = 4 3 x 2 + d 2 ∆ x = 4 3 - 1 x 2 + d 2 = n λ 1 3 x 2 + d 2 = n λ x 2 + d 2 = 9 n 2 λ 2 ∴ P = 3

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