JEE Advanced 2013Paper 1
- Exam
- JEE Advanced
- Year
- 2013
- Paper
- Paper 1
- Subject
- Physics
- Chapter
- Wave Optics
JEE Advanced 2013 · Paper 1 · Physics · Wave Optics
In the Young's double slit experiment using a monochromatic light...
In the Young's double slit experiment using a monochromatic light of wavelength , the path difference ( in terms of an integer ) corresponding to any point having half the peak intensity is
Options
- A\left(2 \text{n} + 1\right) \dfrac{λ}{2}
- B\left(2 \text{n} + 1\right) \dfrac{λ}{4}
- C\left(2 \text{n} + 1\right) \dfrac{λ}{8}
- D\left(2 \text{n} + 1\right) \dfrac{λ}{16}
Correct answer
B. \left(2 \text{n} + 1\right) \dfrac{λ}{4}
Step-by-step solution
∴ 2 \text{I} = 2 \text{I} + 2 \text{I} cos θ
\text\cos θ = 0 \to θ = \left(2 \text{n} + 1\right) \dfrac{π}{2}
\dfrac{2 π}{λ} x = \left(2 \text{n} + 1\right) \dfrac{π}{2}
\text{x} = \dfrac{\left(2 \text{n} + 1\right) λ}{4}