In a Young's double slit experiment, the separation between the two slits is d and the wavelength of the light is λ . The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2 .

Correct answer: A. If d=λ , the screen will contain only one maximum For d=λ , there will be only one, acentral maxima. For λ < d < 2 λ , there will be three maximas on the screen corresponding to path difference, Δ x=0 and Δ x=± λ correct options are (a) and (b).

JEE Advanced 2008Paper 1

Exam: JEE Advanced
Year: 2008
Paper: Paper 1
Subject: Physics
Chapter: Wave Optics

JEE Advanced 2008 · Paper 1 · Physics · Wave Optics

In a Young's double slit experiment, the separation between the two...

In a Young's double slit experiment, the separation between the two slits is

d

and the wavelength of the light is

\lambda

. The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2 . Choose the correct choice(s),

Options

AIf $d=\lambda$ , the screen will contain only one maximum
BIf $\lambda < d < 2 \lambda$ , at least one more maximum (besides the central maximum) will be observed on the screen
CIf the intensity of light falling on slit 1 is reduced so that it becomes equal to that of slit 2 , the intensities of the observed dark and bright fringes will increase
DIf the intensity of light falling on slit 2 is increased so that it becomes equal to that of slit 1 , the intensities of the observed dark and bright fringes will increase

Correct answer

A. If $d=\lambda$ , the screen will contain only one maximum

Step-by-step solution

For

d=\lambda

, there will be only one, acentral maxima. For

\lambda < d < 2 \lambda

, there will be three maximas on the screen corresponding to path difference,

\Delta x=0

and

\Delta x=\pm \lambda

correct options are (a) and (b).

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