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JEE Advanced 2024Paper 1
Exam
JEE Advanced
Year
2024
Paper
Paper 1
Subject
Physics
Chapter
Waves and Sound

JEE Advanced 2024 · Paper 1 · Physics · Waves and Sound

A source (S) of sound has frequency 240 ~Hz . When the observer (O)...

A source (S) of sound has frequency 240 Hz240 \mathrm{~Hz}. When the observer (O)(\mathrm{O}) and the source move towards each other at a speed vv with respect to the ground (as shown in Case 1 in the figure), the observer measures the frequency of the sound to be 288 Hz288 \mathrm{~Hz}. However, when the observer and the source move away from each other at the same speed vv with respect to the ground (as shown in Case 2 in the figure), the observer measures the frequency of sound to be n Hzn \mathrm{~Hz}. The value of nn is ______ A source (S) of sound has frequency 240 ~Hz . When the observer (O) and the source move towards each other at a speed v

Correct answer

0

Step-by-step solution

Frequency received by observer f0=(C±V0C±VS)fsf_0=\left(\frac{C \pm V_0}{C \pm V_S}\right) f_{\mathrm{s}}, C is speed of sound Case-1: f1=(C+VC−V)fs288=(C+VC−V)240\begin{aligned} & \mathrm{f}_1=\left(\frac{\mathrm{C}+\mathrm{V}}{\mathrm{C}-\mathrm{V}}\right) \mathrm{f}_{\mathrm{s}} \\ & 288=\left(\frac{\mathrm{C}+\mathrm{V}}{\mathrm{C}-\mathrm{V}}\right) 240\end{aligned} Case-2: f2=(C−VC+V)fSn=(C−VC+V)240f_2=\left(\frac{C-V}{C+V}\right) f_S \mathrm{n}=\left(\frac{\mathrm{C}-\mathrm{V}}{\mathrm{C}+\mathrm{V}}\right) 240 multiply the two equations, we get. (288)(n)=(240)(240)n=200\begin{aligned} & (288)(\mathrm{n})=(240)(240) \\ & \mathrm{n}=200\end{aligned}
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