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JEE Advanced 2023Paper 2
Exam
JEE Advanced
Year
2023
Paper
Paper 2
Subject
Physics
Chapter
Waves and Sound

JEE Advanced 2023 · Paper 2 · Physics · Waves and Sound

An ideal gas is in thermodynamic equilibrium. The number of degrees...

An ideal gas is in thermodynamic equilibrium. The number of degrees of freedom of a molecule of the gas is nn. The internal energy of one mole of the gas is Un{U}_{n} and the speed of sound in the gas is vn{v}_{n}. At a fixed temperature and pressure, which of the following is the correct option?

Options

  1. Av3<v6{v}_{3} < {v}_{6} and U3>U6{U}_{3} > {U}_{6}
  2. Bv5>v3{v}_{5} > {v}_{3} and U3>U5{U}_{3} > {U}_{5}
  3. Cv5>v7{v}_{5} > {v}_{7} and U5<U7{U}_{5} < {U}_{7}
  4. Dv6<v7{v}_{6} < {v}_{7} and U6<U7{U}_{6} < {U}_{7}

Correct answer

C. v5>v7{v}_{5} > {v}_{7} and U5<U7{U}_{5} < {U}_{7}

Step-by-step solution

As we know, internal energy of one mole of the gas Un=nRT2{U}_{n} = \dfrac{nRT}{2}.

Clearly, Un∝n{U}_{n} ∝ n, where nn is degree of freedom. Therefore, as nn increases, Un{U}_{n} also increases.

Now, speed of sound in gas

vn=\gammaRTM=(1+2n)RTM{v}_{n} = \sqrt{\dfrac{\gammaRT}{M}} = \sqrt{\dfrac{\left(1 + \dfrac{2}{n}\right)RT}{M}}

Clearly, as nn increases and vn{v}_{n} decreases.

Hence,

U7>U5{U}_{7} > {U}_{5} and U7>U6{U}_{7} > {U}_{6}

and v5>v7{v}_{5} > {v}_{7}.

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