JEE Advanced 2019Paper 2
- Exam
- JEE Advanced
- Year
- 2019
- Paper
- Paper 2
- Subject
- Physics
- Chapter
- Waves and Sound
JEE Advanced 2019 · Paper 2 · Physics · Waves and Sound
Answer the following by appropriately matching the lists based on...
Answer the following by appropriately matching the lists based on the information given in the paragraph.
A musical instrument is made using four different metal strings, and with mass per unit length and respectively. The instrument is played by vibrating the strings by varying the free length in between the range and It is found that in string- \left(\mu\right){L}_{0}{T}_{0}{f}_{0} .( a )- 1\left(\mu\right)( p )1( b )- 2\left(2\mu\right)( q )\dfrac{1}{2}( c )- 3\left(3\mu\right)( r )\dfrac{1}{\sqrt{2}}( d )- 4\left(4\mu\right)( s )\dfrac{1}{\sqrt{3}}( t )\dfrac{3}{16}( u )\dfrac{1}{16}{T}_{0},{f}_{0} units will be,
A musical instrument is made using four different metal strings, and with mass per unit length and respectively. The instrument is played by vibrating the strings by varying the free length in between the range and It is found that in string- \left(\mu\right){L}_{0}{T}_{0}{f}_{0} .( a )- 1\left(\mu\right)( p )1( b )- 2\left(2\mu\right)( q )\dfrac{1}{2}( c )- 3\left(3\mu\right)( r )\dfrac{1}{\sqrt{2}}( d )- 4\left(4\mu\right)( s )\dfrac{1}{\sqrt{3}}( t )\dfrac{3}{16}( u )\dfrac{1}{16}{T}_{0},{f}_{0} units will be,
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Fundamental frequency is maximum when length is minimum i.e.
Case (fundamental frequency of vibration in string fixed at both ends)
Case
Case
Case
Case (fundamental frequency of vibration in string fixed at both ends)
Case
Case
Case