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JEE Advanced 2019Paper 1
Exam
JEE Advanced
Year
2019
Paper
Paper 1
Subject
Physics
Chapter
Waves and Sound

JEE Advanced 2019 · Paper 1 · Physics · Waves and Sound

A train S1, moving with a uniform velocity of 108km / h, approaches...

A train S1,S1, moving with a uniform velocity of 108km/h,108km / h, approaches another train S2S2 standing on a platform. An observer OO moves with a uniform velocity of 36km/h36km / h towards S2,S2, as shown in figure. Both the trains are blowing whistles of same frequency 120Hz.120Hz . When OO is 600m600m away from S2S2 and distance between S1S1 and S2S2 is 800m,800m, the number of beats heard by OO is____
[Speed of the sound =330m/s]= 330m / s ]
A train S1, moving with a uniform velocity of 108km / h, approaches another train S2 standing on a platform. An

Correct answer

0

Step-by-step solution

Speed of sound= 300ms300\dfrac{m}{s}
Calculate beat freq{f}_{req}
A train S1, moving with a uniform velocity of 108km / h, approaches another train S2 standing on a platform. An
fb=∣f1−f2∣{f}_{b} = \left|{f}_{1} - {f}_{2}\right|
Where, f1{f}_{1} and f2{f}_{2} are the apparent frequencies of train S1{S}_{1} and S2{S}_{2} observed by observer.
∴∴ Using Doppler's effect,
⇒fb=120[(330+10cos⁡53°330−30cos⁡37°)−(330+10330)]=120[336306−3433]=8.128Hz⇒ {f}_{b} = 120\left[\left(\dfrac{330 + 10\cos 53 °}{330 - 30\cos 37 °}\right) - \left(\dfrac{330 + 10}{330}\right)\right] = 120\left[\dfrac{336}{306} - \dfrac{34}{33}\right] = 8.128Hz

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